For the reactant stoichiometry shown, enter the compound formula and state of al

Question

1. For the reactant stoichiometry shown, enter the compound formula and state of all substances that are products. Separate by comma. Click NONE if no reaction. CsOH(aq) + HClO4(aq) ?
2. For the reactant stoichiometry shown, enter the compound formula and state of all substances that are products. Separate by comma. Click NONE if no reaction. NaHSO4(aq) + NaOH(aq) ?
3. For the reactant stoichiometry shown, enter the compound formula and state of all substances that are products. Separate by comma. Click NONE if no reaction. 2NH4Cl(aq) + Ba(OH)2(aq) ?
4. Enter the formula of the missing substance ( Y ) and its state in the balanced equation below. Do not give its coefficent. Ba(OH)2(aq) + 2Y ? Ba(PF6)2(aq) + 2H2O(l)
5. For the stoichiometry shown, complete and balance the chemical equation using compound formulas. Be sure to include the states of the reactants and products. Click NR if no reaction. 2HCO2H(aq) + Sr(OH)2(aq) ?
6. The reaction of aqueous perchloric acid and aqueous barium hydroxide is represented by the balanced formula equation. 2HClO4(aq) + Ba(OH)2(aq) ? Ba(ClO4)2(aq) + 2H2O(l) Give the balanced net ionic equation for the reaction.

Explanation / Answer

(1) Cs(OH)(aq) + HClO4(aq) => CsClO4(aq) + H2O(l)


(2) NaHSO4(aq) + NaOH(aq) => Na2SO4(aq) + H2O(l)


(3) 2 NH4Cl(aq) + Ba(OH)2(aq) => BaCl2(aq) + 2 NH3(aq) + 2 H2O(l)

or 2 NH4Cl(aq) + Ba(OH)2(aq) => BaCl2(aq) + 2 NH4OH(aq)


(4) Y = HPF6

Ba(OH)2(aq) + 2 HPF6 => Ba(PF6)2(aq) + 2H2O(l)


(5) 2 HCO2H(aq) + Sr(OH)2(aq) => Sr(HCO2)2(aq) + 2 H2O(l)


(6) Expand ions to get total ionic equation:

2 H+(aq) + 2 ClO4-(aq) + Ba2+(aq) + 2 OH-(aq)

=> Ba2+(aq) + 2 ClO4-(aq) + 2 H2O(l)


Cancel common terms and divide by 2 to get net ionic equation:

H+(aq) + OH-(aq) => H2O(l)

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