How much dry solute would you take to prepare each of the following solutions fr
ID: 822595 • Letter: H
Question
How
much dry solute would you take to prepare each of the following solutions from the dry solute and the solvent?
Part A 116mL of 0.105M NaNO3
Part B 135g of 0.200m NaNO3
gNaN3 Part C 135g of 1.7% NaNO3 solution by mass
Part D How much solvent would you take to prepare the solution in part B? msolvent =
gH2O
Part E How much solvent would you take to prepare the solution in part C? msolvent =
gH2O Provide Feedback
Copy of CHEM 1212K
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How
much dry solute would you take to prepare each of the following solutions from the dry solute and the solvent?
Part A 116mL of 0.105M NaNO3
Part B 135g of 0.200m NaNO3
gNaN3 Part C 135g of 1.7% NaNO3 solution by mass
Part D How much solvent would you take to prepare the solution in part B? msolvent =
gH2O
Part E How much solvent would you take to prepare the solution in part C? msolvent =
gH2O Provide Feedback
How
much dry solute would you take to prepare each of the following solutions from the dry solute and the solvent?
Part A 116mL of 0.105M NaNO3
Part B 135g of 0.200m NaNO3
gNaN3 Part C 135g of 1.7% NaNO3 solution by mass
Part D How much solvent would you take to prepare the solution in part B? msolvent =
gH2O
Part E How much solvent would you take to prepare the solution in part C? msolvent =
gH2O
How
much dry solute would you take to prepare each of the following solutions from the dry solute and the solvent?
Part A 116mL of 0.105M NaNO3
Part B 135g of 0.200m NaNO3
gNaN3 Part C 135g of 1.7% NaNO3 solution by mass
Part D How much solvent would you take to prepare the solution in part B? msolvent =
gH2O
Part E How much solvent would you take to prepare the solution in part C? msolvent =
gH2O
How
much dry solute would you take to prepare each of the following solutions from the dry solute and the solvent?
Part A 116mL of 0.105M NaNO3
Part B 135g of 0.200m NaNO3
gNaN3 Part C 135g of 1.7% NaNO3 solution by mass
Part D How much solvent would you take to prepare the solution in part B? msolvent =
gH2O
Part E How much solvent would you take to prepare the solution in part C? msolvent =
gH2O
How
much dry solute would you take to prepare each of the following solutions from the dry solute and the solvent?
Part A 116mL of 0.105M NaNO3
How
much dry solute would you take to prepare each of the following solutions from the dry solute and the solvent?
Part A 116mL of 0.105M NaNO3
Part B 135g of 0.200m NaNO3
gNaN3
Part B 135g of 0.200m NaNO3
gNaN3
gNaN3
gNaN3 Part C 135g of 1.7% NaNO3 solution by mass
Part C 135g of 1.7% NaNO3 solution by mass
Part D How much solvent would you take to prepare the solution in part B? msolvent =
gH2O Part D How much solvent would you take to prepare the solution in part B? msolvent =
gH2O msolvent =
gH2O msolvent =
gH2O
Part E How much solvent would you take to prepare the solution in part C? msolvent =
gH2O
Part E How much solvent would you take to prepare the solution in part C? msolvent =
gH2O msolvent =
gH2O msolvent =
gH2O Provide Feedback
Copy of CHEM 1212K
- Signed in as Muhammad Khan
- Help
- Close
- Signed in as Muhammad Khan
- Help
- Close
- Signed in as Muhammad Khan
- Help
- Close
- Signed in as Muhammad Khan
- Help
- Close
How
much dry solute would you take to prepare each of the following solutions from the dry solute and the solvent?
Part A 116mL of 0.105M NaNO3
Part B 135g of 0.200m NaNO3
gNaN3 Part C 135g of 1.7% NaNO3 solution by mass
Part D How much solvent would you take to prepare the solution in part B? msolvent =
gH2O
Part E How much solvent would you take to prepare the solution in part C? msolvent =
gH2O Provide Feedback
Explanation / Answer
remember that molarity, M, is moles solute / liters solvent
so, M x V = moles solute
0.105M x 0.116L = 0.01218 moles NaNO3
0.01218 moles NaNO3 x 85g/mole = 1.0353g
0.2 m NaNO3 in a total of 135g --> 0.2m x 0.135kg = 0.0270 moles NaNO3 required
0.0270 g x 85g/mole = 2.295 g
1.7% of 135g = 0.017 x 135 = 2.295 g solute
1 .2.295 g NaNO3 required in the total mass of 135g so 132.705 g solute required
2 .2.295 g solute in the total mass of 135g solution so 132.705 g solvent
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