Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

In the lab there is a bottle of sulfuric acid. The label on the bottle reads: 9.

ID: 821719 • Letter: I

Question

In the lab there is a bottle of sulfuric acid. The label on the bottle reads: 9.364 M, 15.795 m sulfuric acid. Find density and percent of sulfuric acid in this solution. In the lab there is a bottle of sulfuric acid. The label on the bottle reads: 9.364 M, 15.795 m sulfuric acid. Find density and percent of sulfuric acid in this solution. In the lab there is a bottle of sulfuric acid. The label on the bottle reads: 9.364 M, 15.795 m sulfuric acid. Find density and percent of sulfuric acid in this solution.

Explanation / Answer

molality m = Molarity(M)*1000/D*1000-M*M.Wt

D= density, M.WT = molecularweight.

15.795 =9.364*1000/D*1000-9.364*98

Density = 1.51 grams/ml.

mass of H2SO4 = 9.364*98 = 917.672 grams.

volume of solution v= 1000 ml

mass of solution = 1000*1.51 = 1510 grams


percent of sulfuric acid =wt of H2SO4/Wt. of solution. = 917.62/1510*100 = 60.77%


Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote