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Given the reactants, find the products and their NIEs. AlCl 3 (aq) + NH 3 (aq) +

ID: 819895 • Letter: G

Question

Given the reactants, find the products and their NIEs.


AlCl3 (aq) + NH3 (aq) + H2O (l) --> Al(OH)3 (s) +


Al3+ (aq) + NH3 (aq) + H2O (l) -->

Al(OH)3 (s) + HNO3 (aq) -->

Al(OH)3 (s) + H+ (aq) -->

Al(NO3)3 (aq) + NaOH (aq) -->  Na[Al(OH)4] (aq) +

Al3+ (aq) + OH- (aq) -->

Na[Al(OH)4] (aq) + HNO3 (aq) -->  NaNO3 (aq) + Al(NO3)3 (aq) + H2O (l)

[Al(OH)4]- (aq) + H+ (aq) -->

Al(NO3)3 (aq) + NH3 (aq) + H2O (l) -->  Al(OH)3 (s) + NH4NO3 (aq)


Al3+ (aq) + NH3 (aq) + H2O (l) -->

Explanation / Answer

Given the reactants

AlCl3 (aq) + NH3 (aq) + H2O (l) -->

the products for the reaction are

AlCl3(aq) + 3NH3(aq) + 3H2O (l) --> Al(OH)3(s) + 3NH4Cl(s)

the net ionic equation for the reaction is

Al3+ (aq) +3NH3 (aq) + 3H2O (l) -----> Al(OH)3(s) + 3NH4+(aq)

Given the reactants

Al3+ (aq) + NH3 (aq) + H2O (l)

the products for the reaction are

Al3+ (aq) +3NH3 (aq) + 3H2O (l) -----> Al(OH)3(s) + 3NH4+(aq)

the net ionic equation is

Al^3+ (aq) + 3H2O(l) -----> Al(OH)3(s) + 3H+(aq)

Given the reaction

Al(OH)3 (s) + HNO3 (aq) -->

the product for the reaction can be written as

Balanced molecular reaction

3HNO3(aq) + Al(OH)3(s) ------> Al(NO3)3(aq) + 3H2O(l)

complete ionic equation

3H+ + 3NO3- + Al(OH)3(s) ------> Al3+ + 3NO3- + 3H2O(l)

Al(OH)3 (s) + H+ (aq) -->

Al(OH)3 (s) + 3H+ (aq) --> Al3+ + 3H2O(l)...

Given the reaction

Na[Al(OH)4] (aq) + HNO3 (aq) --> NaNO3 (aq) + Al(NO3)3 (aq) + H2O (l)

Na[Al(OH)4] (aq) + HNO3 (aq) --> NaNO3 (aq) + Al(NO3)3 (aq) + H2O (l)

[Al(OH)4]- (aq) +3H+ (aq) --> Al(OH)3(s) + H2O(l)

Given the reactants

AlCl3 (aq) + NH3 (aq) + H2O (l) -->

the products for the reaction are

AlCl3(aq) + 3NH3(aq) + 3H2O (l) --> Al(OH)3(s) + 3NH4Cl(s)

the net ionic equation for the reaction is

Al3+ (aq) +3NH3 (aq) + 3H2O (l) -----> Al(OH)3(s) + 3NH4+(aq)

Given the reactants

Al3+ (aq) + NH3 (aq) + H2O (l)

the products for the reaction are

Al3+ (aq) +3NH3 (aq) + 3H2O (l) -----> Al(OH)3(s) + 3NH4+(aq)

the net ionic equation is

Al^3+ (aq) + 3H2O(l) -----> Al(OH)3(s) + 3H+(aq)

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