The air we breath is a mixture of gases nitrogen (N 2 , 80%), oxygen (O 2 , 20%

Question

The air we breath is a mixture of gases nitrogen (N2, 80%), oxygen (O2, 20% inhaled, 16% exhaled) and carbon dioxide (CO2, 0% inhaled, 4% exhaled) all of which may be assumed to behave as ideal gases.

(a) Calculate, in liters (1 L = 10^-3 m3), the volume occupied by 1 mole of air at ambient conditions (1 atm pressure, room temperature T = 21 ?C). The average human inhales only about 2% of that volume in a single breath.

(b) The air is warmed to body temperature (T = 37 degrees C) as it is inhaled. Assuming the volume inhaled is constant, what is the pressure of air in the lungs when inhaled at standard pressure (1 atm) :

from ambient room of temperature T = 70 degrees F= 21 degrees C,

Explanation / Answer

a)pv=nrt

p=1 atm

n=1mole

r=8.31joules

t=70

v=581.98litres

average human inhales is 2/100*581.98=11.64

b)p1/t1=p2/t2

p1/37=1/70

=0.528

b)

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.