n 2009, a team from Northwestern University and Western Washington University re

Question

n 2009, a team from Northwestern University and Western Washington University reported the preparation of a new "spongy" material composed of nickel, molybdenum, and sulfur that excels at removing mercury from water. The density of this new material is 0.20 g/cm3, and its surface area is 1242 m2 per gram of material.

Calculate the volume of a 35.0?mg  sample of this material?

Calculate the surface area for a 35.0?mg  sample of this material.

A 10.0-mL sample of contaminated water had 7.748 mg of mercury in it. After treatment with 10.0 mg of the new spongy material, 0.001 mg of mercury remained in the contaminated water. What percentage of the mercury was removed from the water?

What is the final mass of the spongy material after the exposure to mercury?

Explanation / Answer

1.) volume =200/35 cm3

               =5.71 cm3

2.) surface are= 1.242*35 m2

                    =43.47

3.) percentage of the mercury was removed from the water = 7.747/7.748*100=99.98%

4.) the final mass of the spongy material after the exposure to mercury=10+7.747=17.747 mg

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