The decomposition of nitramide, O2NNH2, in water has the following chemical equa
ID: 816856 • Letter: T
Question
The decomposition of nitramide, O2NNH2, in water has the following chemical equation and rate law. O2NNH2 (aq) yields N2O (g) + H2O (l) rate= [O2NNH2]/[H]
A proposed mechanism for this reaction is.
k1
(1) O2NNH2 (aq) equilibrium O2NNH (aq) + H (aq) (fast equilibrium)
k-1
k2
(2) O2NNH (aq) yields N2O (g) + OH (aq) (slow)
k3
(3) H (aq) + OH yields H2O (l) (fast)
determine the rate laws for each elementary step:
drag the symbols: K1, [O2NNH2], [N2O], K-1, [O2NNH-], K2, [H+], K3, [OH-], [H2O]
rate1=
rate-1=
rate2=
rate3=
Explanation / Answer
1. O2NNH2 (aq) <=> O2NNH (aq) + H (aq) ( k1 = rate constant for forward reaction and k-1= rate constant for backward reaction
rate1=k1[O2NNH2]
rate-1=k-1 [O2NNH-][H+]
2. O2NNH (aq) ----------> N2O (g) + OH (aq) ( k2 = rate constant for forward reaction)
rate2=k2[O2NNH-] (
3. H (aq) + OH ---------------> H2O (l) (k3 = rate constant for forward reaction)
rate3=k3 [H+][OH-]
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