The decomposition of N2O5 can be described by the equation. Given these data for

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The decomposition of N2O5 can be described by the equation. Given these data for the reaction at 45°C in carbon tetrachloride solution, calculate the average rate of reaction for each successive time interval.

Home I Chegg.com Olivia × Germanna Community College × 008 Given these date for the react × d www.sapinglearning.com/ibiscms/mod/ibis/view.php?id=4742167 : AppsBGermanna Communi. G gmail* GERM-SmartThinkingQGCC BOOKSTORE James Madison Uni CHM 112 FOIL SAP PSYCH MINDTAP LO InQuiz tive for Weth. GERM-ePRINTit Loc Sapling Learning macmilan leaming Jump to... Olivia Lange . Sapling Learning Germanna Community College, Fredericksburg CHM 112-F01/F02 -Spring18-RUNNELSActivities and Due Dates HW 14a My Assignment Resources # Attempts Score 2/14/201811:00PM1/11 Print Clculator Periadic Table Available From: Due Date Points Possible: Grade Category: Not Set 2/14/2018 11:00 PM 11 Graded General Chemistry 4th Edtion Science Books The decomposition of N20s can be described by the equation t(s) N0sl (M) 2.28 195 506 1.68 Given these data for the reaction at 45 C in carbon tetrachloride solution, calculate the average rate af reaction for each successive time interval. 1.39 You can check your answers. You can view solutions when you complete or give up on any question. You can keep trying to answer each question until you get it right or give up. You lose 5% of the points available to each answer in your question for each incorrect attempt at that answer Interval: s to 195 s 195 s to 506 s s to 785 s Reaction rate: 13310 M/ s | | | 1,16× 10 M/S 119.68 × 10-4 | M/s 10 0 0 eTextbook Youve found the rates of disappearance of [N2Osl. Use the slcichiometry of the reaction to relate your answers to the reaction rate 11 0 a/N101 Help With This Topic rate=- O Web Help & Videos D Technical Support and Bug Reports Previous Givo Up & View Solution # Try Again Next Ext

Explanation / Answer

rate of reaction = (-1/2)*d[N2O5]/dt
rate of reaction = (-1/2)*(C2-C1)/(t2-t1)

1) 0s to 195 s
rate of reaction = (-1/2)*(C2-C1)/(t2-t1)
= (-1/2)*(2.02 - 2.28) / (195-0)
= 6.67*10^-4 M/s
Answer: 6.67*10^-4 M/s

2) 195 s to 506 s
rate of reaction = (-1/2)*(C2-C1)/(t2-t1)
= (-1/2)*(1.66 - 2.02) / (506-195)
= 5.79*10^-4 M/s
Answer: 5.79*10^-4 M/s

3) from 506s to 785 s
rate of reaction = (-1/2)*(C2-C1)/(t2-t1)
= (-1/2)*(1.39 - 1.66) / (785-506)
= 4.84*10^-4 M/s
Answer: 4.84*10^-4 M/s

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