1) A mixture consisting of 2.336 g naphthalene, 1.556g of NaCl and the remainder

Question

1) A mixture consisting of 2.336 g naphthalene, 1.556g of NaCl and the remainder sand had a total weight of 4.888 g. Calculate the % by mass of each component 2) A sample of a mixture with a total weight of 17.833 g had a composition cl 22.42% sand, 47.77 X salt and the rest naphthalene. Calculate the mess in grams of each component. 3) In a jar of M&M; brand candy there were 46 red. 77 brown, 33 yellow. and 56 green candies. Calculate the % of each candy in the ar (note this is by number not the mass).

Explanation / Answer

Answer: 1) According to question we have

naphthalene = 2.336 g

NaCl = 1.556 g and sand = 4.888 g

Now % naphthalene = mass of naphthalene / total mass * 100

= 2.336 / 8.78 * 100 = 26.60%

% of NaCl = mass of NaCl /total mass * 100 = 1.556 / 8.78 * 100 = 17.72%

% of sand = mass of sand / total mass * 100 = 4.888 / 8.78 * 100 = 55.68 %

so this is the way in which we have calculate the mass %

2} Now in the second question the procedure is same . first we have to calculate the mass of that compound and total mass like :

we have given total mass = 17.833 g

now 22.42% sand means = 17.833 * 22.42 /100 = 3.998 g

47.77 % of salt [NaCl ] = 17.833 * 47.77/100 = 8.52 g

rest would be = 17.833 -[3.998+ 8.52] = 5.315 g

Hence this is way in which we have calculate all this things

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