United Nations toxicologist studying the properties of mustard gas, S(CH 2 CH 2

Question

United Nations toxicologist studying the properties of mustard gas, S(CH2CH2Cl)2, a blistering agent used in warfare, prepares a mixture of 0.675 M SCl2 and 0.973 MC2H4 and allows it to react at room temperature (20.0

United Nations toxicologist studying the properties of mustard gas, S(CH2CH2Cl)2, a blistering agent used in warfare, prepares a mixture of 0.675 M SCl2 and 0.973 MC2H4 and allows it to react at room temperature (20.0 A degree C ). SCl2(g) + 2 C2H4(g) S(CH2CH2Cl)2(g) At equilibrium, [S(CH2CH2Cl)2] = 0.350 M. Calculate Kp.

Explanation / Answer

SCl2 + 2 C2H4 <=> S(CH2CH2Cl)2

C -x -2x +x
E 0.675-x 0.973-2x x

x = 0.350 M

[SCl2] = 0.325 M
[C2H4] = 0.273 M

Kc = 0.350/(0.325*0.273^2)
Kc = 14.45

Kp = Kc(RT)^(dn)
dn = moles of products - moles of reactants = -2

Kp = Kc(RT)^-2 = 14.45(8.314*(20+273.15)/101.325)^-2
Kp = 0.0250

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