What is the concentration of F 2 over a bath of molten cryolite at this temperat

Question

What is the concentration of F2 over a bath of molten cryolite at this temperature?

Aluminum is one of the most versatile metals. It is produced by the Hall-Heroult process, in which molten cryolite, Na3AlF6, is used as a solvent for the aluminum ore. Cryolite undergoes very slight decomposition with heat to produce a tiny amount of F2, which escapes into the atmosphere above the solvent. Kc is 2 3 Na(l) + Al(l) + 3 F2(g) What is the concentration of F2 over a bath of molten cryolite at this temperature? x 10^-104 at 1300 K for the reaction. Na3AlF6(l)

Explanation / Answer

For the equation given

Kc = [F2]^3 which I guess is the 2 x 10^-104

liquids are not included in eqm constant expressions. Then solve for [F2] by taking the cube root.

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