Two sequential hydrogenation reactions take place in a continuous reactor at ste

Question

Two sequential hydrogenation reactions take place in a continuous reactor at steady state.

C2H2+H2->C2H4

C2H4+H2->C2H6

The feed stream contains 25.0 mole% C2H2, 56.0 mole% H2 and 19.0 mole% inerts. The fractional conversion of C2H2 to C2H4 is 0.770 and the fractional conversion of C2H4 to C2H6 is 0.510.

If the basis of the feed stream is 100 mol, what are the moles of each gas in the product stream?

1. number of mol C2H2

2.number of mol of C2H4

3.number of mol of C2H6

4. number of mol of H2

5.mol inerts

What is the total moles of gas in the product stream?

6. mol

What is the percent by mole of each gas in the product stream?

1. % C2H2

2. % C2H4

3. % C2H6

4. % H2

5. % inerts

Explanation / Answer

Basis of feed stream = 100 moles

moles in feed of C2H2 = 25 moles

moles in feed of H2 = 56 moles

moles in feed of Inerts = 19 moles

fractional conversion of C2H2 to C2H4 = 0.770

moles of C2H2 left = 0.23*25

= 5.75 moles

moles of C2H4 formed = 0.770*25

= 19.25 moles

conversion of C2H4 = 0.510

moles of C2H6 formed = 0.510*19.25

= 9.8175 moles

moles of C2H4 left = 19.25 - 9.8175

= 9.4325 moles

for 19.25 mol C2H4 to be formed 19.25 mol H2 is needed

for 9.8175 mol C2H6 to be formed 9.8175 mol H2 is needed

total H2 consumed = 19.25 + 9.8175

= 29.0675 moles

moles of H2 left = 56 - 29.0675

= 26.933 moles

moles of inert = 19 moles

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