Two seperate strings are attatched to a spherical bob having a mass of 300g and

Question

Two seperate strings are attatched to a spherical bob having a mass of 300g and to a central rod. The central rod is turned such that the revolving bob travels in a horizonal circle with a radius of 45 cm. While the system is rotating, the strings each make an angle of 30 degrees with the horizonal, one above the horizonal and the other below. If the period of revolution is 0.60s, determing the magnitude of the tension in each string. [Hint: They are not equal]

Two separate strings are attached to a spherical bob having a mass of 300g and to a central rod. The central rod is turned such that the revolving bob travels in a horizonal circle with a radius of 45 cm. While the system is rotating, the strings each make an angle of 30 degrees with the horizonal, one above the horizonal and the other below. If the period of revolution is 0.60s, determing the magnitude of the tension in each string.

Explanation / Answer

Vertical component = T * sin ?, ? is the angle below the horizontal plane.
The sum of the vertical components of the tension is supporting the weight of the bob as he the toy moves around the horizontal circle.

t=0.6 then f=0.166 w=2pi*f=0.3pi

Ta * sin ?a + Tb * sin ?b = mass * g = 0.3* 9.81
?a = 210?
?b = 150?
mass = 300 kg
Equation #1
Ta * sin 210? + Tb * sin 150? = 2.943
Ta * -5 + Tb * .5 = 2.943
Divide both sides by -0.5

Eq. #1: Ta

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