%3Cp%3EA%200.251%26nbsp%3Bg%26nbsp%3Bsample%26nbsp%3Bof%26nbsp%3Boctane(C8H18)%2
ID: 801380 • Letter: #
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%3Cp%3EA%200.251%26nbsp%3Bg%26nbsp%3Bsample%26nbsp%3Bof%26nbsp%3Boctane(C8H18)%26nbsp%3Bis%26nbsp%3Bburned%26nbsp%3Bcompletely%26nbsp%3Bin%26nbsp%3Bthe%26nbsp%3Bpresence%26nbsp%3Bof%26nbsp%3Bexcess%26nbsp%3Boxygen%26nbsp%3Bto%26nbsp%3Bproduce%26nbsp%3Bcarbon%26nbsp%3Bdioxide%26nbsp%3Bgas%26nbsp%3Band%26nbsp%3Bwater%26nbsp%3Bvapor.%26nbsp%3BThe%26nbsp%3Breaction%26nbsp%3Bvessel%26nbsp%3Bis%26nbsp%3B1.50%26nbsp%3Bliters%26nbsp%3Band%26nbsp%3Bthe%26nbsp%3Btemperature%26nbsp%3Bof%26nbsp%3Bthe%26nbsp%3Bvessel%26nbsp%3Bat%26nbsp%3Bthe%26nbsp%3Bend%26nbsp%3Bof%26nbsp%3Bthe%26nbsp%3Breaction%26nbsp%3Bis%26nbsp%3B105%26nbsp%3BC.%3C%2Fp%3E%3Cp%3E%3Cbr%3E%3C%2Fp%3E%3Cp%3EWhat%26nbsp%3Bus%26nbsp%3Bthe%26nbsp%3Bpartial%26nbsp%3Bpressure%26nbsp%3B(in%26nbsp%3Batm)%26nbsp%3Bof%26nbsp%3Bcarbon%26nbsp%3Bdioxide%26nbsp%3Band%26nbsp%3Bthe%26nbsp%3Bpartial%26nbsp%3Bpressure%26nbsp%3B(in%26nbsp%3Batm)%26nbsp%3Bof%26nbsp%3Bwater%26nbsp%3Bvapor%3F%26nbsp%3B(For%26nbsp%3Bthe%26nbsp%3Bpurpose%26nbsp%3Bof%26nbsp%3Bthis%26nbsp%3Bquestion%2C%26nbsp%3Bassume%26nbsp%3Bideal%26nbsp%3Bgas%26nbsp%3Bbehavior.)%3Cbr%3E%3C%2Fp%3E%3Cp%3E%3Cbr%3E%3C%2Fp%3EExplanation / Answer
A 0.251 g sample of octane(C8H18) is burned completely in the presence of excess oxygen to produce carbon dioxide gas and water vapor. The reaction vessel is 1.50 liters and the temperature of the vessel at the end of the reaction is 105 C. What is the partial pressure (in atm) of carbon dioxide and the partial pressure (in atm) of water vapor (for the purpose of this question assume ideal gas behavior.
P=nRT/V
P=[ (0.251 g / 114.23 g/mol) * (0.08201) * (105 +273) ] / (1.50 L)
P=0.0454 atm (This is for the total pressure of the system)
2C8H18(l) + 25O2(g) ------> 16CO2( g)+18H2O(g) (This is the balanced equation)
Px=Ptotal(nx/ntotal)
PCO2=0.0454(16/34) and PH2O=0.454(18/34)
PCO2=0.0214 atm and PH20=0.02403 atm
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