%3Cp%3E%3Cspan%20style%3D%22color%3A%26nbsp%3Brgb(51%2C%26nbsp%3B51%2C%26nbsp%3B
ID: 820413 • Letter: #
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/ Answer
a. the mass of CO2 = 87.719-g - 87.642-g = 0.077-g moles of CO2 = .077-g / 44.0-g/mol = 0.00175 mol
b. the vapor pressure of water at 20 oC is 17.5 Torr, so the pressure of the dry CO2: 770 -17.5 =
752.5 Torr
d. PV = nRT ---> V = nRT/P 0.00175 mol x 62.396-L*Torr/mol*K x 293-K/ 752.5 Torr = 0.0425-L = 42.5-mL at 20oC and 752.5 Torr . Corrected to STP : P1V1/T1 = P2V2/T2 ---> V2 = P1V1T2/P2T1
752.5-Torr x 42.5-mL x 273-K / (760-Torr x 293-K) = 39.2-mL at STP
equation: CaCO3 + 2HCl ---> CaCl2 + CO2 + H2O
e. 0.00175 mol CaCO3 x ( 1 mol CO2 / 1 mol CaCO3) x (22,400-mL/ 1 mol CO2) = 39.2-mL CO2
f. molar ratio is 1:1 (1 mole CaCO3 produces 1 mole of CO2). Thus moles of CaCO3 is 0.00175 moles
g. 0.00175 mol CaCO3 x (100.1-g CaCO3 / 1 mol CaCO3) = 0.175-g CaCO3
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