The answer is 3.6x10^-3 M. How do you solve this? An electrochemical cell to mea

Question

The answer is 3.6x10^-3 M. How do you solve this?

An electrochemical cell to measure [Cl-] was constructed by placing a AgCl(s)-coated Ag wire in a 1.00 M KCl solution in one compartment of the cell. The unknown Cl- solution is placed in the other compartment along with another AgCl(s)-coated Ag wire. The potential difference between the Ag wires was then measured with a voltmeter. The potential of the Ag wire in the compartment containing the unknown Cl- was found to be +0.1445 V vs. the other Ag wire. What is the [Cl-] of the unknown solution?

Explanation / Answer

E CELL=0.059/2 log [C2]/[C1]

0.1445=0.059/2 log1/[C1]

log1/C1=2*0.1445/0.059

C1=0.00001M

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