You cross two bunnies which were heterozygous for the two genes that control bun

Question

You cross two bunnies which were heterozygous for the two genes that control bunny color, BbHh, and you obtain the following progeny: 9 brown bunnies, 3 yellow bunnies, and white bunnies. You think that this result indicates that bunny color is controlled by epistasis. What is epistasis and how would it give these results? In humans, color blindness X^b, is an X-linked recessive trait. A woman that is heterozygous for normal vision marries a color blind man a. What are the genotypes of each of the parents?

Explanation / Answer

c) AbBb offspring is formed from a cross AaBb X AABB, the punnett square is as follows: -

Hence, based the above, An offspring AaBb from the cross between AaBb X AABB is 1/4.

3) As the color-blind allele is linked to the X chromosome and mother is heterozygous for the allele then,

genotype of the mother would be XbX (as mother has 2X chromosome) and

genotype of the father would be XbY (as father has single X chromosome)

genotype AB Ab aB ab AB AABB AABb AaBB AaBb AB AABB AABb AaBB AaBb AB AABB AABb AaBB AaBb AB AABB AABb AaBB AaBb

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