You cross two bunnies which were heterozygous for the two genes that control bun

Question

You cross two bunnies which were heterozygous for the two genes that control bunny color, BbHh, and you obtain the following progeny: 9 brown bunnies, 3 yellow bunnies, and white bunnies. You think that this result indicates that bunny color is controlled by epistasis. What is epistasis and how would it give these results? In humans, color blindness X^b, is an X-linked recessive trait. A woman that is heterozygous for normal vision marries a color blind man a. What are the genotypes of each of the parents? b. What genotypes and phenotypes are possible in the offspring?

Explanation / Answer

a. Women heterozygous for normal vision means she is a carrier.Her genotype will be XBXb where XB represents carrier.

Mother : XBXb

Since color blind is a X linked recessive trait,in males the presence of color blind gene on one X chromosome results in color blindness.So,color blind man will have the gene expressed on his X chromosome.So, the genotype will be XbY.

Father : XbY.

b. Father

The genotypes and phenotypes will be as below:

Genotype Phenotype

XBXB   color blind daughter

XBXb normal carrier daughter

XBY normal son

XbY colorblind son

Mother XB Y XB XBXB   color blind daughter XBY normal son Xb XBXb   normal carrier daughter XbY colorblind son

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