1. A hot tub with a surface area of 25 ft^2 is filled with water to a deph of 28
ID: 799162 • Letter: 1
Question
1. A hot tub with a surface area of 25 ft^2 is filled with water to a deph of 28 inches.
a. what is the volume, in liters, of the water in the hot tub?
b. what is the mass, in kilograms, of the water it contains?
c. how many kilocalories are needed to heat the water from 62 degree F to 105 degrees F?
d. If the hot tub heater provided 5900 KJ/min how long in hours will it take to heat the water from 62 degrees F to 105 degrees F
2. Match the following physical and chemical properties with octane C8H18 found in gasoline or magnesium sulfate, MgSO4 Aka epsom salt
_____contains only covalent bonds
_____melts @ 1124 degrees C
MgSoO4-conducts eletricity
_____does not contain ions
3. Write a balanced equation for each reaction and ID the type of reaction
a. Bismuth III oxide and carbon react to form bismuth metal and carbon momoxide
b. Sodium cglorate is heated to form sodium chloride and oxygen
c. butane reacts with oxygen to form Co2 and H20
4. write the electron configuration for barium II ion
5. Predict the products for the following reactions and balance the equations
a. combustion Al + 02
b. Single replacement Fe + H20
c. double replacement Al2S3 + H20
d. combination of nitrogen and hydrogen
6. A 92 g sample of a liquid is placed in a 25 liter flask at 140 degrees Celsius the liquid evaporates completely to a pressure of .900 atm
a. what is the molar mass
b. if the flask can withstand pressure up to 1.30 atm calculate the max temperature to which the gas can be heated without breaking
Explanation / Answer
Q1)
a)
29*28/12=58.33 ft^3
b)
mass=volume*rho=58.33*0.0283*1000=1650.83 kg
c)
62F=16.67C and 105F=40.56
no. of kcal required=1*delT*mass(in g)=39438.41 kcal
d)
1kJ=4.186kcal
so, no. of hours required=39438.41*4.186/5900/60=0.466 hours
Q2)
C8H18
C8H18
answers for 1st and 4th part
MgSO4 answers for 2nd and third
Q4)
The electronic configuration of Ba2+ is the configuration of Ba excluding the last two 6s2 electrons. The configuration is just like Xenon.
It is - 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10 5s2 5p6.
Q3)
a)
Bi2O3+3C========>2Bi+3CO
b)
3NaClO3+heat=======>3NaCl+3O2
c)
C4H10+13/2O2=======>4CO2+5H2O
Q5)
a)
2Al+3/2O2=====>2Al2O3
b)
2Fe + 3H2O = Fe2O3 + 3H2
c)
Al2S3(s) + 6H2O(l) ----> 2Al(OH)3(s) + 3H2S(g)
d)
N2+3H2====>2NH3
Q6)
a)
PV=nRT (T=140+273=413)
so,
n=0.9*25/8.314/413=6.6*10^-3;
molar mass=92/n=14039.9 g/mol
b)
P1/T1=P2/T2 (P1=0.9 and P2=1.3 T1=413)
so, T2=596.56 K =323.56 C
is the maximum temperature it can be heated without breaking
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