1. Calculate the average translational kinetic energy (sometimes just called ave
ID: 798739 • Letter: 1
Question
1. Calculate the average translational kinetic energy (sometimes just called average kinetic energy)...
a. for one mole of gas at 365 K. Answer: E(k)=_____J/mol
b. for a single gas molecule at 365 K. Answer E(k)=_____J/molecule
2. If He(g) has an average kinetic energy of 6350 J/mol under certain conditions, what is the root mean square speed of N2(g) molecules under the same conditions? Answer: _____ m/s
3. The average kinetic energy of the molecules in a gas sample depends only on the temperature, T. But given the same kinetic energies, a lighter molecule will move faster than a heavier molecule.
where R=8.314 J/(mol
Explanation / Answer
a) avg.K.E FOR n MOLE=3/2nRT
= 3/2*1**8.314*365
=4551.9j/mole
b) avg k.e for molecule=3/2*K*T
=3/2*1.38*10^-23*365
=755.5*10^-23J/MOLECULE
2)
avg.K.E FOR n MOLE=3/2nRT
6350=3/2*1*8.314*T
T=509.1K
R.M.S=( 3RT/M)^1/2
=(3*8.314*509.1/28*10^-3)^1/2
226785.71met/SEC
3)a)
R.M.S= (3RT/M)^1/2
= (3*8.314*375/32 *10^-3)^1/2
=146144.5 met/sec
b)
R.M.S= (3RT/M)^1/2
= (3*8.314*375/4*10^-3)^1/2
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