The vapor pressures of benzene ( C 6 H 6 ) and hexane ( C 6 H 14 ) at 75 The vap

Question

The vapor pressures of benzene (C6H6) and hexane (C6H14) at 75

The vapor pressures of benzene (C6H6) and hexane (C6H14) at 75 degree C are 648 mm Hg and 921 mm Hg, respectively. If 310.0 g benzene is mixed with 710.0 g hexane at 75 degree C, what are the mole fractions of benzene and hexane in this solution? mole fraction of benzene mole fraction of hexane Assuming this is an ideal system that obeys Raoult's law, find the partial vapor pressure of each component over the solution. vapor pressure of benzene vapor pressure of hexane

Explanation / Answer

Moles of benzene = 330 / 78 = 4.231

Moles of Hexane = 760 / 86 = 8.837

Mole fraction of benzene = 4.231 / (4.231 + 8.837) = 0.3238

Mole traction of Hexane = 1 - 0.3238 = 0.6762

b) VP of benzene = 03238 x 648 = 209.8 mm Hg

VP of Hexane = 0.6762 x 921 = 622.81 mm Hg

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