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The vapor pressure of liquid propyl amine, C_3 H_7 NH_2, is 100. mm Hg at 274 K.

ID: 1068501 • Letter: T

Question

The vapor pressure of liquid propyl amine, C_3 H_7 NH_2, is 100. mm Hg at 274 K. A sample of C_3 H_7 NH_2 is placed in a closed, evacuated 515 mL container at a temperature of 274K. It is found that all of the C_3 H_7 NH_2 is in the vapor phase and that the pressure is 72.0 mm Hg. If the volume of the container is reduced to 343 mL at constant temperature, which of the following statements are correct? Choose all that apply. The pressure in the container will be 108 mm Hg. Only propyl amine vapor will be present. Liquid propyl will be present. No condensation will occur. Some of the vapor initially present will condense.

Explanation / Answer

Ans :

Pressure in the container will be 108 mmHg

P1V1/T1 = P2V2/T2

P1 = 72 mmHg, V1 = 515 mL , T1 = T2 = 274 K , V2 = 343 mL, P2 = ?

P2 = 72*515*274/274*343

P2 = 108.1 mmHg

Liquid propyl amine will be present

The vapor pressure of the propyl amine at 274 K is 100 mmHg.

The calculated pressure is 108.1 mmHg which is greater that vapor pressure. Therefore liquid will be present.