What is the molar concentration of a KBrO 3 {\ m KBrO}_{3} solution if 27.80mL {

Question

What is the molar concentration of a KBrO 3 { m KBrO}_{3} solution if 27.80mL { m mL} of the solution is needed to titrate 1,545g {m g} of As 2 0 3 ? {m As}_{2}{ m 0}_{3}? The balanced equation is 3H 3 AsO 3 (aq)+BrO 3 ? (aq)?Br ? (aq)+3H 3 AsO 4 (aq) 3{ rn H}_{3X m AsO}J3}(aq) + {{ m BrO}_{3}}*B(aq) ight arrow{m BrH-}(aq) + 3{ m H}_{3}{ rn AsO}_{4}(aq) (As 2 0 3 {m As}_{2X^rm 0}_{3} dissolves in aqueous acid solution to yield H 3 AsO 3 :As 2 0 3 +3H 2 0?2H 3 AsO 3 { m H}_{3X m AsO}_{3}: { m As}_{2K m 0}_{3} + 3{ m H}_{2K^rm 0> X right arrov^ 2{ m H}_{3K m AsO}_{3})

Explanation / Answer

use these formulas to put ur values

The overall balanced equation is:
3 As2O3 + 9 H2O + 2 KBrO3 ? 2 KBr + 6 H3AsO4

(1.550 g As2O3) / (197.8415 g As2O3/mol) x (2/3) / (0.02630 L) = 0.1986 mol/L

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