Ok, so here\'s the question: For the reaction between H2 and I2, a proposed mech
ID: 795959 • Letter: O
Question
Ok, so here's the question:
For the reaction between H2 and I2, a proposed mechanism is
step 1: I2 ?2 I (fast equilibrium)
step 2: 2 I + H2? 2 HI (slow)
What rate law do you expect to be observed for the overall reaction?
My book gives me this solution:
From step 2,
rate = k2[I]2[H2]
From step 1, k1f[I2] = k1r[I]2
[I]2 = (k1f/k1r)[I2]
Substituting for [I]2 in the rate law, we have
rate = k2(k1f/k1r)[I2][H 2] = k[I2][H2]
The Problem is...
I don't really understand this explaination at all. Specifically the last part, where it says "Substituting for [I]2 in the rate law...", and then the subsequent equation. Visually I can't see how they got what they got. So I need a simple, but detailed, worded explaination please. Thank you!!
Explanation / Answer
step 2: 2 I + H2? 2 HI (slow)
slow step of the reaction is used determine Rate law
but 2I is not exactly the reactent it is intermediate
so as per the calculations given [I]^2 = (k1f/k1r)[I2]
substituting this value inrate eq.
rate = k2[I]2[H2]
rate = k2(k1f/k1r)[I2][H 2] = k[I2][H2] (k2(k1f/k1r) = consatnt or rate constant
so that we can obtain rate = K2[I2][H2]
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