Iron metal reacts with hydrochloric acid as follows: 2Fe( s ) + 6HCl( aq ) ? 2Fe

Question

Iron metal reacts with hydrochloric acid as follows: 2Fe(s) + 6HCl(aq) ? 2FeCl3(aq) + 3H2(g) If 22.4 g of iron react with excess HCl, and 59.4 g of FeCl3 are collected, what is the percent yield of the reaction? Answer A. 73.0% B. 109% C. 65.0% D. not enough information given E. 91.4% Iron metal reacts with hydrochloric acid as follows: 2Fe(s) + 6HCl(aq) ? 2FeCl3(aq) + 3H2(g) If 22.4 g of iron react with excess HCl, and 59.4 g of FeCl3 are collected, what is the percent yield of the reaction? Iron metal reacts with hydrochloric acid as follows: 2Fe(s) + 6HCl(aq) ? 2FeCl3(aq) + 3H2(g) If 22.4 g of iron react with excess HCl, and 59.4 g of FeCl3 are collected, what is the percent yield of the reaction? 2Fe(s) + 6HCl(aq) ? 2FeCl3(aq) + 3H2(g) If 22.4 g of iron react with excess HCl, and 59.4 g of FeCl3 are collected, what is the percent yield of the reaction? 73.0% 109% 65.0% not enough information given 91.4% A. 73.0% B. 109% C. 65.0% D. not enough information given E. 91.4%

Explanation / Answer

E)91.4%

22.4 g Fe x (1 mol Fe)/(55.84 g Fe) x (2 mol FeCl3)/(2 mol Fe) x (162.2 g FeCl3)/(1 mol FeCl3)

The theoretical yield is 65.066 g FeCl3.

percent yield = actual yield / theoretical yield multiplied by 100%

(59.4 g FeCl3 / 65.066 g FeCl3) x 100

The percent yield equals 91.3%

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