A cell consists of a gold wire and a saturated calomel electrode (S.C.E.) in a 0

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A cell consists of a gold wire and a saturated calomel electrode (S.C.E.) in a 0.190 M AuNO3 solution at 25

A cell consists of a gold wire and a saturated calomel electrode (S.C.E.) in a 0.190 M AuNO3 solution at 25 degreeC. The gold wire is connected to the positive end of a potentiometer, and the S.C.E. is connected to the negative end of the potentiometer. What is the half-reaction for the Au electrode? Ignoring activities, if the standard reduction potential for the above reaction is Edegree = 1.69 V, what is potential of the gold electrode? The reduction potential for the saturated calomel electrode is E = 0.241 V. What is the cell voltage?

Explanation / Answer

1.as we know dat the cell potential is given by

E=E0-(0.05916/n) * log(1/[Au+]

putting the value from the given question we ve

E=1.69-(0.05916/1) * log (1/0.190)

E=1.64733 V

2 . Cell voltage ll be = 1.64733 - 0.241 = 1.40633 V

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