You measure the initial rate of an enzyme reaction as a function of substrate co

Question

You measure the initial rate of an enzyme reaction as a function of substrate concentration in the presence and absence of an inhibitor. The following data are obtained:

[S]

V0

  

[S]

     

V0

You measure the initial rate of an enzyme reaction as a function of substrate concentration in the presence and absence of an inhibitor. The following data are obtained: What is th Vmax in the absence of inhibitor? What is the Km in the absence of inhibitor? When [S] = 0.0004, what will V0 be in the absence of inhibitor? When [S] = 0.0004, what will V0 be in the presence of inhibitor? What kind of inhibitor is it likely to be?

Explanation / Answer

a) 100 (highest Vo) at highest substrate concentrations

b) 0.002 (because Km= 1/2 Vmax and since Vmax is 100 see what [S] is at 50)

c) When [S] = 0.0004, what will V0 be in the absence of inhibitor?

because, Vmax= 100, Km= 0.0002(1/2Vmax)

so, Vo = Vmax [S]/Km + [S]

Vo = 100 (0.0004)/0.0002 + 0.0004

so, Vo = 66.7

d) When [S] = 0.0004, what will V0 be in the presence of inhibitor?

because, Vmax= 100, Km= 0.0005 (1/2Vmax)

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