question 1 Nickel (II) hydroxide is found in rechargeable batteries (NiCd batter
ID: 793142 • Letter: Q
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question 1 Nickel (II) hydroxide is found in rechargeable batteries (NiCd batteries). The following examples show three pertinent reactions of Ni(OH)2 in water. What is the mass balance expression for the hydroxide in this system? Ni(OH)2 (s) question 1 Nickel (II) hydroxide is found in rechargeable batteries (NiCd batteries). The following examples show three pertinent reactions of Ni(OH)2 in water. What is the mass balance expression for the hydroxide in this system? Ni(OH)2 (s) question 1 Nickel (II) hydroxide is found in rechargeable batteries (NiCd batteries). The following examples show three pertinent reactions of Ni(OH)2 in water. What is the mass balance expression for the hydroxide in this system? Ni(OH)2 (s)Explanation / Answer
1) d [Ni(OH)2] + [H2O}= [OH-] + [NiOH+]
2)
3) ionic strength (in M) of a 0.050 M Ca(NO3)2+ 0.098 M Mg(NO3)2.
no of ions of Ca(NO3)2= ca+2 +2no3- = 3ions
total ionic strength Ca(NO3)2= 3*0.05 = 0.15M
no of ions of Mg(NO3)2. = mg 2+ +2no3-
total ionic strength Mg(NO3)2.= 0.098*3 = 0.294
total ionic strength of reaction = 0.15+0.294=0.444M
4)
Calculate the solubility of Ag2SO4(silver sulfate) in water as mol/L. Ksp = 1.5 x 10-5(Express your answer as a decimal to 2 significant figures.)
Ag2SO4(s) ------> 2Ag^+(aq) + SO4^2-(aq)
Ksp = [Ag^+]^2[SO4^2-] = 1.5 x 10^-5
4x^3 = 1.5 x 10^-5
x = 0.0155M
solubility = 0.0155M = 0.016 M
5)
Using activities, calculate the solubility of Ag2SO4(silver sulfate) in 0.010 M KNO3. Ksp = 1.5 x 10-5. (You may ignore the contribution of Ag+and SO42-to the ionic strength. Express your answer in
In this problem we will consider the common ion effect.
Dissolving of 0.10 M AgNO3 produces 0.10 M Ag^+ ion.
AgNO3(s) ------> Ag^+(aq) + NO3^-(aq)
0.10 M -------------> 0.10 M + 0.10 M
Total [Ag^+] in solution: ( 0.10 + 2x ) M
But 2x M from the dissolving of Ag2SO4 is very small compared to the ion present in the solution, it can be neglected.
Ksp = (0.10)^2(x) = 1.2 x 10^-5
x = 1.2 x 10^-4 mol / L is the solubility of salt in 0.10 M AgNO3
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