an experiment was performed to determine the formula of the hydrated ionic salt:

Question

an experiment was performed to determine the formula of the hydrated ionic salt: BaCl2 x H2O. the weight of the BaCl2 was found to be 1.564 grames and the H2O was found to be 0.2820 grams'

                                         mass      relative # of mol          Divide by smallest mol                Smallest whole #

Barium chloride_________________________________________________________________________

water                __________________________________________________________________________

Explanation / Answer

Barium chloride = 1.564

H2O = 0.2820 gms

moles of Bacl2 = 1.564/208.23 = 7.5*10^-3

so moles of H2O = 7.5*10-3 = 0.2820/x*18

x*18 = 37.54

x= 2.08 that means formula is BaCl2 2 H2O

mass percent of bacl2 = 1.564/1.564+0.2820 = 1.564/1.846*100 = 84.72%

mass of water = 15.27%

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