an electron in the cathode ray tube of a television set enters a region where it

Question

an electron in the cathode ray tube of a television set enters a region where it accelerates uniformly from a speed of 34400 m/s to a speed of 4.08e6 m/s in a distance of 2.48cm 1.what is its acceleration? (m/s^2) 2.for what length of time is the electron in this region where it accelartes? an electron in the cathode ray tube of a television set enters a region where it accelerates uniformly from a speed of 34400 m/s to a speed of 4.08e6 m/s in a distance of 2.48cm 1.what is its acceleration? (m/s^2) 2.for what length of time is the electron in this region where it accelartes?

Explanation / Answer

1.The electron accelerates uniformly from a speed of u = 34400 m/s to a speed of v = 4.08e6 m/s = 4.08 * 10^6 m/s in a distance of S = 2.48 cm = 2.48 * 10^-2 m Let it's acceleration be a We know from the relation v^2 - u^2 = 2aS or a = (v^2 - u^2/2S) 2.Let the length of time be t We know that S = ut + (1/2)at^2 Solving the above equation for t we get the time

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