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please help number and show work and steps so i can understand it and follow it

What is the maximum amount in grams of CO2 produced when 6.00 grams of carbon combines with oxygen gas? In the following reaction: 2 K(s) + 2H2O(l) rightarrow 2KOH(aq) +H2g) What amount of KOH is produced if you have 100 g of each reactant? Which reactant is limiting? Magnesium oxide can be made by heating magnesium metal in the presence of oxygen. When 10.1 g of Mg are allowed to react with 10.S g of O2 11.9 g of MgO are collected. Determine the limiting reactant. theoretical yield and percent yield for the reaction. Consider the following reaction: CaO(s) + CO2(g) rightarrow CaC03(s) A chemist allows 14.4 g of CaO and 13.8 g of CO2 to react When the reaction is finished, the chemist collects 19.4 g of CaCC3 Determine the limiting reactant, theoretical yield and percent yield

Explanation / Answer

6)

c+o2 ------------> co2

6gms -----------= 6/12 = 0.5 moles

0.5 moles of carbon gives 0.5 moles of co2

so max co2 formed = 0.5*44 =22 gms

7)

1mole of k react with one mole water gives one mole of KOH

moles of K = 100/ 39 = 2.56moles

gives 2.56 moles of KOH = 2.56 * molar mass of KOH = 2.56 *56 = 143.58gms

8)

2 mg+ o2 -----------> 2mgo

moles of mg= 10.1 /24 = 0.42

moles of o2 = 10.5/ 32 = 0.328moles

limiting reagent is magneiusm

theoritical yeidl = 0.42/2 * 40 = 0.21*40 = 8.4gms

percent yeild= 8.4 *100/11.9 = 70.5%

9)

cao +co2 ------>caco3

moles of cao = 14.4 /56 =0.257

moles of o2 = 13.8 /32 =0.431

limiting reagent is cao because of less no of moles

theoritical yield = 0.257 *100 = 25.7 gms

percent yeild= 19.4*100 /25.7 = 75.48%

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