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ID: 2292979 • Letter: P

Question

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Start Typing in MATLAB 7.1 Erercise 1 1 023 0 2 | in MATLAB. ( you know how to enter a Enter the matrix C = | 4-1 matrix in MATLAB) a) Find a basis for the row(C). 0 - -8-10 Type vectors that form a basis for the row space of C. Type your answer as R1C for the first vector and R2C for the second vector and R3C, as many as needed: R2C b) Find a basis for the rou() Type vectors that form a basis for the row space of C. Type your answer as R1CT for the first vector and R2CT for the second vector and R3C, as many as needed: RICT = c) Find a basis for the col(C). Type vectors that form a basis for the column space of C. Type your answer as CiC for the first vector and C2C for the second vector and R3C, as many as needed: Cic C2C d) Find a basis for the col(C) Type vectors that form a basis for the column space of C. Type your answer as CICT for the first vector and C2CT for the second vector and C3CT, as many as needed: C3CT- d) Find rank(C) and rank(C) by typing RanC-rank(C) and RanCt-rank(C) Write down dimension of rou(C) and col (C) as: 10 Drowspace type your answer here Dcolspace type your answer here

Explanation / Answer

C = [1 0 2 3; 4 -1 0 2; 0 -1 -8 -10]

%a)....................................................colspace() returns basis of selected row or coloumn

R1=[1 0 2 3]

R2=[4 -1 0 2]

R3=[0 -1 -8 -10]

R1C=colspace(sym(R1))

R2C=colspace(sym(R2))

R3C=colspace(sym(R3))

%c)

C1=[1 ;4 ;0]

C2=[0 ;-1 ;-1]

C3=[2 ;0 ;-8]

C4=[3 ;2 ;-10]

C1C=colspace(sym(C1))

C2C=colspace(sym(C2))

C3C=colspace(sym(C3))

C4C=colspace(sym(C4))

%(b) and (d)...................................................rows of matrix C becomes columns of matrix C'

R1CT=colspace(sym(C1))

R2CT=colspace(sym(C2))

R3CT=colspace(sym(C3))

R4CT=colspace(sym(C4))

C1CT=colspace(sym(R1))

C2CT=colspace(sym(R2))

C3CT=colspace(sym(R3))

%e)

RanC=rank(C)

RanCt=rank(C')

%rank = 2 for both C and C'

Drowspace=1x4

Dcolspace=3x1