The Born-Haber cycle is a series of steps that represent the formation of an ion

Question

The Born-Haber cycle is a series of steps that represent the formation of an ionic compound from a metal and a nonmetal.  For example, the steps in a Born-Haber cycle for the formation of NaCl(s) consist of sublimation of the metal Na atom (?Hsubl-Na) to form a gaseous Na atom, bond dissociation of the chlorine molecule (BECl2)  to form a gaseous Cl atom, ionization energy of the sodium atom (IENa) to form a gaseous Na+ ion, electron affinity of the chlorine atom (EACl) to form a gaseous Cl- ion, and the lattice energy of NaCl (LENaCl) involving the coalescing of the gaseous Na+ and Cl- ions to form a solid NaCl formula unit.

With the above summary in mind, which particular steps of the Born-Haber cycle would be represented in the following reaction?   

K(s) + F(g) ? KF(s)

A. ?Hsubl-K, IEK, EAF, and LEKF B. IEK,EAF, and LEKF C. ?Hsubl-K, BEF2, IEK, EAF, and LEKF D. ?Hsubl-K, BEF2, IEK, EAF

Explanation / Answer

The answer is:

A. ?Hsubl-K, IEK, EAF, and LEKF


To get the overall reaction: K(s) + F(g) => KF(s)

The following processes are involved:

K(s) => K(g): ?Hsubl-K

K(g) => K+(g) + e-: IEK

F(g) + e- => F-(g): EAF

K+(g) + F-(g) => KF(s): LEKF

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