Part A Calculate the density of oxygen, O 2 , under each of the following condit

Question

Part A Calculate the density of oxygen, O2, under each of the following conditions:

• STP
• 1.00 atm and 25.0 ?C

Express your answers numerically in grams per liter. Enter the density at STP first and separate your answers by a comma. g/L SubmitHintsMy AnswersGive UpReview Part Part B To identify a diatomic gas (X2), a researcher carried out the following experiment: She weighed an empty 0.65-L bulb, then filled it with the gas at 2.00atm and 24.0 ?C and weighed it again. The difference in mass was 1.5g. Identify the gas. Express your answer as a chemical formula. SubmitHintsMy AnswersGive UpReview Part
Help me solve?? Part A Calculate the density of oxygen, O2, under each of the following conditions:

• STP
• 1.00 atm and 25.0 ?C

Express your answers numerically in grams per liter. Enter the density at STP first and separate your answers by a comma. g/L SubmitHintsMy AnswersGive UpReview Part Part A Calculate the density of oxygen, O2, under each of the following conditions:

• STP
• 1.00 atm and 25.0 ?C

Express your answers numerically in grams per liter. Enter the density at STP first and separate your answers by a comma. g/L SubmitHintsMy AnswersGive UpReview Part g/L g/L SubmitHintsMy AnswersGive UpReview Part Part B To identify a diatomic gas (X2), a researcher carried out the following experiment: She weighed an empty 0.65-L bulb, then filled it with the gas at 2.00atm and 24.0 ?C and weighed it again. The difference in mass was 1.5g. Identify the gas. Express your answer as a chemical formula. SubmitHintsMy AnswersGive UpReview Part
Help me solve?? Part B To identify a diatomic gas (X2), a researcher carried out the following experiment: She weighed an empty 0.65-L bulb, then filled it with the gas at 2.00atm and 24.0 ?C and weighed it again. The difference in mass was 1.5g. Identify the gas. Express your answer as a chemical formula. SubmitHintsMy AnswersGive UpReview Part
Help me solve?? SubmitHintsMy AnswersGive UpReview Part
Help me solve?? g/L

Explanation / Answer

for part A = we can use the formula PM = dRT

so for conditions at stp we get density = 1bar *32=d*0.0821*273

d=1.40 gm /ml

for second cond. we apply the same formula to get d= 1atm*32/0.0821*298

d=1.30gm/ml

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.