Part A Astrology, that unlikely and vague pseudoscience, makes much of the posit
ID: 1882699 • Letter: P
Question
Part A Astrology, that unlikely and vague pseudoscience, makes much of the position of the planets at the moment of one's birth. The only known force a planet exerts on Earth is gravitational. Calculate the gravitational force exerted on a 3.90 kg baby by a 77.0 kg father 0.170 m away at birth (he is assisting, so he is close to the child). Submit Answer Tries 0/10 Part B Calculate the force on the baby due to Jupiter if it is at its closest distance to Earth, some 6.29% 1011 m away. Submit Answer Tries 0/10 Part C How does the force of Jupiter on the baby compare to the force of the father on the baby, i.e., find the ratio of the force due to the father over the force due to Jupiter? (Other objects in the room and the hospital building also exert similar gravitational forces. Of course, there could be an unknown force acting, but scientists first need to be convinced that there is even an effect, much less that an unknown force causes it.)Explanation / Answer
(A) We know that the gravitational force is given by
F = GMm/r2
Where G is gravitational constant = 6.67*10-11
M is mass of father = 77 kg
m is mass of baby = 3.9 kg
r is distance between the baby and father = 0.170 m
F1 = (6.67*10-11)*(77*3.9) /(0.172) = 6.931*10-3 N
(b) Now force between baby and jupiter
mass of jupiter (MJ) = 1.898*1027 kg
F= GMJ*m /r2
where r is distance between baby and jupiter = 6.29*1011 m
F2 = 6.67*10-11*(1.898*1027)*(3.9) /(6.29*1011)2
= 1.248*10-6 N
(C) Now = F1/F2
F1/F2 = 6.931*10-3 /1.248*10-6
F1/F2 = 5553.686
hence we can say that force by the father is 5553.686 times to the force by the jupiter
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