3 H 2 ( g ) + N 2 ( g ) ? 2 N H 3 ( g ) The ammonia produced in the Haber-Bosch
ID: 787150 • Letter: 3
Question
3H2(g)+N2(g)?2NH3(g)
The ammonia produced in the Haber-Bosch process has a wide range of uses, from fertilizer to pharmaceuticals. However, the production of ammonia is difficult, resulting in lower yields than those predicted from the chemical equation.
The Haber-Bosch process is a very important industrial process. In the Haber-Bosch process, hydrogen gas reacts with nitrogen gas to produce ammonia according to the equation3H2(g)+N2(g)?2NH3(g)
The ammonia produced in the Haber-Bosch process has a wide range of uses, from fertilizer to pharmaceuticals. However, the production of ammonia is difficult, resulting in lower yields than those predicted from the chemical equation.
1.21g H2 is allowed to react with 9.56g N2, producing 2.52g NH3.Part A ) What is the theoretical yield for this reaction under the given conditions?
Part B) What is the percent yield for this reaction under the given conditions?
Explanation / Answer
1) 1.21 gm H2 = 1.21/2 = 0.605 moles
N2 moles = 9.56/28 = 0.3414 moles
H2 is limiting reagent ( since it will be consumed whole while N2 will be left excess)
NH3 moles = ( 2/3)(0.605) = 0.4033
NH3 theortical yield = 0.4033 x17 = 6.85 gm
b) % yield = ( 2.52/6.85) x100 = 36.79 %
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