3 H2(g)=N2(g)- 2NH3 How many molecules of N2 react with 40 molecules of H2 How m

Question

3 H2(g)=N2(g)- 2NH3 How many molecules of N2 react with 40 molecules of H2
How many moles of NH3 are formed with 15 moles of N2
How many miles of NH3 are formed from 10.0 g H2 3 H2(g)=N2(g)- 2NH3 How many molecules of N2 react with 40 molecules of H2
How many moles of NH3 are formed with 15 moles of N2
How many miles of NH3 are formed from 10.0 g H2 3 H2(g)=N2(g)- 2NH3 How many molecules of N2 react with 40 molecules of H2
How many moles of NH3 are formed with 15 moles of N2
How many miles of NH3 are formed from 10.0 g H2 How many molecules of N2 react with 40 molecules of H2
How many moles of NH3 are formed with 15 moles of N2
How many miles of NH3 are formed from 10.0 g H2

Explanation / Answer

Q1.

ratio is 1 mol of N2 = 3 mol of NH3

40 molecules of H2 --> 1/3*40 = 13.3 molecules of N2 required, nearest will be "14" molecules

Q2.

ratio is 1 mol of N2 = 2 mol of NH3

15 moles of N2 --> 2*15 = 30 mol of NH3 produced

Q3

mol of H2 = mass/MW = 10/2 = 5 mol

raito is 3 mol of H2 = 2 mol of NH3

5 mol of H2 --> 2/3*5 = 3.3333 moles of NH3 will form

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