Hydrogen gas, H2, reacts with nitrogen gas, N2, to form ammonia gas, NH3, accord

Question

Hydrogen gas, H2, reacts with nitrogen gas, N2, to form ammonia gas, NH3, according to the equation 3H2(g)+N2(g)?2NH3(g) NOTE: Throughout this tutorial use molar masses expressed to five significant figures. Part A How many moles of NH3 can be produced from 12.0mol of H2 and excess N2? Express your answer numerically in moles. Part B How many grams of NH3 can be produced from 2.12mol of N2 and excess H2. Express your answer numerically in grams. Part C How many grams of H2 are needed to produce 12.91g of NH3? Express your answer numerically in grams. Part D How many molecules (not moles) of NH3 are produced from 1.68

Explanation / Answer

1) Firstly, find the moles of NH3. No. of moles = mass/molar mass (on periodic table). The number of moles of H2 will then be: 3/2 x no. of moles of NH3. The fraction 3/2 is the ratio of the coefficients of these substances in the reaction. Now, convert this to mass by using the formula: m = n x M where n is the no. of moles and M is the molar mass.

2) Find the no. of moles of H2: n = m/M then find the no. of moles of NH3: 2/3 x n(H2). Divide the no. of moles by Avogadro's Number which is 6.022 x 10^23 and you will have the no. of molecules of NH3.

Always remember that the fraction is obtained by the coefficient of the unknown (the one you're trying to find) divided by the coefficient of the known then multiply by the known no. of moles.

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