1. In this experiment, aluminum will be converted into potassium aluminum sulpha

Question

1. In this experiment, aluminum will be converted into potassium aluminum sulphate dodecahydrate. This process requires three reactions. Balance these three reactions.

a.)  Al (s) + KOH (aq) + HOH (l) ---> KAl(OH)4 (aq) + H2 (g)

b.) KAl (OH)4 (aq) + H2SO4 (aq) --> KAl(SO4)2 (aq) + H2O (l)

c.) KAl(SO4)2 (aq) + H2O (l) ---> KAl(SO4)2  * 12H2O (s)

2. Under experimental procedures #2 and #3, the experiment calls for reacting aluminum with water and potassium hydroxide. See 1a above for the equation. A student using quantities:

3.00 grams Al

15.0 mL of 8.00 M KOH

75.0 mL distilled HOH

Which of the reactants is the limiting reactant? (Mathematically document this.) Show your work and set up.

PLEASE HELP ME ON MY PRE LAB QUESTION FOR CHEM 121 My manual is call Cu IN Lab. THANK YOU SO MUCH :)

Explanation / Answer

1. In this experiment, aluminum will be converted into potassium aluminum sulpha

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