A sample of an unknown peptide undergoes a single round of Edman degradation, wh
ID: 786077 • Letter: A
Question
A sample of an unknown peptide undergoes a single round of Edman degradation, which liberates ATZ-Gly. Another sample of the peptide is treated with trypsin, and a third sample is treated with chymotrypsin. The table below shows the fragments.
Tryptic fragments:
Phe-Ser
Gly-Val-Tyr-Arg
Asn-Tyr-Ala-Pro-Thr-Cys-Val-Gln-Lys
Chymotryptic fragments:
Arg-Asn-Tyr
Ala-Pro-Thr-Cys-Val-Gln-Lys-Phe
Ser
Gly-Val-Tyr
A) line up the fragments so that the fragments with the same sequences overlap.
B) Write the sequence of the peptide
Explanation / Answer
Edman degradation removes amino acid fron N-terminal,
so, as Gly is liberated during Edman degradation, it means Gly is at the N- terminal
A)
Tryptic fragments: will be lines up as
Gly-Val-Tyr-Arg ---Asn-Tyr-Ala-Pro-Thr-Cys-Val-Gln-Lys ---- Phe-Ser
Chymotryptic fragments: will be lined up as
Gly-Val-Tyr --- Arg-Asn-Tyr ---- Ala-Pro-Thr-Cys-Val-Gln-Lys-Phe --- Ser
B)
sequence of the peptide is
Gly-Val-Tyr-Arg -Asn-Tyr-Ala-Pro-Thr-Cys-Val-Gln-Lys- Phe-Ser
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.