Given the following: Finding Percent H 2 O 2 with Yeast Volume of O 2 collected

Question

Given the following: Finding Percent H2O2 with Yeast

Volume of O2 collected = .014L

Temperature of water (in K): 299k

Pressure (in atm): 0.04 atm

What are the actual moles of O2 collected ?

What are the

Theoretical moles of O2 (assume 100% H2O2 density = 1.02 g/mL):?

What is the

Percent H2O2: and the  Reaction rate: ?

Show work

Given the following: Finding Percent H2O2 with Yeast Volume of O2 collected = .014L Temperature of water (in K): 299k Pressure (in atm): 0.04 atm What are the actual moles of O2 collected ? What are the Theoretical moles of O2 (assume 100% H2O2 density = 1.02 g/mL):? What is the Percent H2O2: and the Reaction rate: ? Show work

Explanation / Answer

PV=nRT

0.04*0.014=n*0.0821*299

n=2.28*10^-5

mass of O2 collected=Mol. wt*no. of moles=32*2.28*10^-5=7.3*10^-4g

PM=(rho)*R*T

0.04*M=1.02*0.0821*299

Related Questions

Navigate

• Browse (All)
• Browse G
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.