1. Calculate the number of sodium ions in (6.107x10^1) g sodium phosphate. 2. An
ID: 784628 • Letter: 1
Question
1. Calculate the number of sodium ions in (6.107x10^1) g sodium phosphate.
2. An aqueous solution of 10.0 grams of ammonium sulfide is mixed with an aqueous soluion of 10.0 grams of copper (II) chloride.
What is the formula of the compound that precipitates?
How many grams of precipitate are formed?
3a.Write a balanced equation for the reaction of manganese metal with nitric acid to produce aqueous manganese(II) nitrate and hydrogen gas.
3b.How would you classify this reaction(precipitation, acid-base neutralization,single displacement,combination, decomposition or combustion?
3c. What compound is getting oxidized
3d. What is the oxidation number of nitrogen in nitric acid?
4.How many liters of oxygen gas at (7.410x10^2) torr and 22.0 deg. Celcius are needed for the complete combustion of (3.73x10^0) moles of propane, C3H8?
C3H8(g) + 5O2(g) = 3CO2+4H2O
5. After (4.340x10^-1)L of Ar at (1.120x10^0)atm and 227 deg. celcius is mixed with (2.99x10^-1)L of O2 at (5.390x10^2) torr and 127 deg. Celcius in a (3.890x10^2) mL flask at 300K. Wha
Explanation / Answer
1.) 61.07g Na3PO4*(1mole/163.944g)*(6.022X10^23fu/1mole)*(3 ions/1fu)
=6.73X10^23 sodium ions
2.) CuS
10g*(1mole/134.45g CuCl2)*(95.61g/1mole CuS) = 7.111 grams CuS
3a) Mn (s) + 2HNO3 (aq) --> Mn(NO3)2 (aq) + H2 (g)
3b) Single displacement
3c) Mn (s)
3d) +5
4) V = nRT/P = 465.5 Liters O2
5) Use n=PV/(RT) to find both moles of argon and moles of oxygen
0.01185 moles Ar
0.006460 moles O2
Use P = nRT/V to find final pressure
Final pressure = 1.159 atm
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