The V_max for the reaction when the inhibitor is present is: A. 5 mu mole/min B.

Question

The V_max for the reaction when the inhibitor is present is: A. 5 mu mole/min B. 0.2 mu mole/min C. 0.2 mu mole D. 10 mu mole/min Make sure you know all kinds of enzyme inhibition that were taught in class (how Km and Vmax are affected) What happens when glucose level falls inside a bacterial cell? Study all the different post-transcriptional control of gene expressions in bacteria and eukaryotes. What is epigentic inheritance? What are the different examples of epigenetic inheritance, that you have studied in class? How will you recognize an interphase cell under the microscope? Know how telomerase maintains chromosome ends very well. Is telomerase a reverse transcriptase enzyme? What are the the different features of heterochromatin and euchromatin? How is homologus recombination for DNA repair different from homologous recombination that creates diversity in meiosis? Study how phospholipid and glycolipids are synthesized in ER and Golgi What are glycoproteins and what are their functions? What are the features of integral and peripheral membrane proteins? Study bacteriorhodopsin very well. How does the Na^+ K^+ ATPase pump, work mechanistically (know all the steps? Which inhibitor inhibits the sodium potassium pump and how does it inhibit the pump? How do Curare and GABA? (know the mechanism of action). Which transporter is used by animal and plant cells to maintain pH in the cytosol?

Explanation / Answer

The reaction or diagram necessary to answer question 26 is missing. Let me help you out with the next question.

Ans 27.

When the glucose levels fall inside a bacterial cell, the levels of cAMP increase. This cAMP binds to cAMP receptor protein and forms a complex cAMP - CRP complex.

This complex now enhances the binding of RNA polymerase to the promoter and starts the transcription.

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