The VSEPR model predicts the O-O-O bond angle in O_3 to be A) 120 degree. B) 90
ID: 522782 • Letter: T
Question
The VSEPR model predicts the O-O-O bond angle in O_3 to be A) 120 degree. B) 90 degree. C) less than 120 degree but greater than 190.5 degree. D) 109.5 degree. Which of the following compounds is ethanol? A) CH_3CO_2CH_3 B) CH_3CO_2H C) C_2H_5OH D) CH_3OCH_3 E) C_2H_6 The mole fraction of methane in dry air near sea level is 0.0000020, where the molar mass of methane is 16.043. The partial pressure of methane when the total pressure (dry air) is 97.5 kPa is _____ kPa. A) 3.07 times 10^6 B) 1.97 times 10^-4 C) 0.00316 D) 4.93 times 10^7 E) 1.23 times 10^-5Explanation / Answer
Q38.
The model predicts it to be between 120 and 109.5. since it has resonance, therefore it is between double and single bonds
Q39
ethanol = eth- 2 carbons, -ol = OH group
so
CH3CH2OH --- C2H5OH
best answer is C
Q40
Find parital pressure of methane...
P = 97.5 kPa
P-Methane = x-methane * Ptotal = 0.000002*97.5 = 0.000195 = 1.95*10^-4
best answer is B
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