\"Graph the following data for vapor pressure of ammonia using excel or another
ID: 781627 • Letter: #
Question
"Graph the following data for vapor pressure of ammonia using excel or another computer program and from the graph determine the heat of vaporization and the normal boiling point for NH3"
Temperature in Kelvins Vapor Pressure (Torr)
200 65.3
210 134.3
220 255.7
230 456
235 597
Assuming the equation ln(Vapor Pressure) = molar heat of vaporization/R(1/Temperature)+C, I got a linear approximation of the curve as y=.564x+3.734, with y=ln(Vapor Pressure) and x=1/Temperature, but this gives me values for molar heat of vaporization and normal boiling point that seem way off and too small. I should be getting something around 240-something K for boiling point right?
Explanation / Answer
actually the error is : the slope of line is :
ln (134.3) - ln(65.3) /(1/210 - 1/200) = -3028.553
So it should be y = -3028.553x + c
where you would be able to find c , so thats where the error is , Please rate
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.