How much heat energy, in kilojoules, is required to convert 79.0 g of ice at %u2

Question

How much heat energy, in kilojoules, is required to convert 79.0g of ice at %u221218.0 %u2218C to water at 25.0 %u2218C ? The constants for H2O are shown here:

• Specific heat of ice: sice=2.09 J/(g%u22C5%u2218C)
• Specific heat of liquid water: swater=4.18 J/(g%u22C5%u2218C)
• Enthalpy of fusion: %u0394Hfus=334 J/g
• Enthalpy of vaporization: %u0394Hvap=2250 J/g

How much heat energy, in kilojoules, is required to convert 79.0g of ice at %u221218.0 %u2218C to water at 25.0 %u2218C ? The constants for H2O are shown here:

• Specific heat of ice: sice=2.09 J/(g%u22C5%u2218C)
• Specific heat of liquid water: swater=4.18 J/(g%u22C5%u2218C)
• Enthalpy of fusion: %u0394Hfus=334 J/g
• Enthalpy of vaporization: %u0394Hvap=2250 J/g

Explanation / Answer

Energy = 79*2.09*19 + 79*334 + 79*4.18*25

=37778.59 J = 37.78 Kj

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