A GC analysis was conducted on a soil sample containing pollutant X. The followi

Question

A GC analysis was conducted on a soil sample containing pollutant X. The following separations were conducted:

                                                                                        Tr(min)                      peak area

Injection 1 21.1 ppm Toluene Internal Standard            10.11                         36,242

                   33.4 ppm X                                                   14.82                        45,997

Injection 2 21.1 ppm Toluene Internal Standard            10.05                         38,774

                  unknown concentration X                              14.77                        39,115

What is the concentration of X in the sample?

Explanation / Answer

Aa/[a]=F*As/[s],

where

Aa is the area of the analyte signal,

[a] is the concentration of the analyte(can be in grams),

F is the response factor,

As is the area of the standard signal, and

[s] is the concentration of the standard(in grams).

by first data

( 36,242)/( 21.1) = F * ( 45,997/33.4)

F = 1.247

Now for unknown concentration

( 38,774)/(21.1) = 1.247 * ( 39,115/X)

X = 26.55 ppm

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