Answer Answer Solution The formation reaction of alanine is given by : N2 + C +

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The formation reaction of alanine is given by : N2 + C + H2+O2 -----------------------> NH2CH(CH3)COOH(s) ..................1 delta Ho( ala ,s ) = ?? (say a) The enthalpy of combustion of 1 mol of alanine is : NH2CH(CH3)COOH(s) + (19/2) O2(g) ===> 3 CO2(g) + (7/2) H2O(liq) + (1/2) N2(g).....2 DeltacombHo = -1623.0 kJ / mol. (say b ) The enthalpy of formation of 1 mol of CO2(g) : C+02 ----------------------->CO2 ......................3 enthalpies of formation of CO2(g) = -393.51 kJ / mol (say c) The enthalpy of formation of 1 mol of H2O(l) is : H2+1/2O2------------------->H20 ..................................4 enthalpies of formation of H20(l) = -285.83 kJ/mol (say d) b-3*c+(7/2)*d NH2CH(CH3)COOH(s) + (19/2 - 3- 7/2) O2(g) -3C -7H2------------>(1/2) N2(g) NH2CH(CH3)COOH(s) + (3) O2(g) -3C -7H2------------>(1/2) N2(g) ..................5 enthalpies of formation = b-3*c+(7/2)*d = -1623 - 3*(-393.51)+3.5(-285.83) kJ/mol = -1442.87 kJ/mol Reversing equation 5 we get 1/2) N2(g) - (3) O2(g) +3C +7H2------------>( NH2CH(CH3)COOH(s) DeltafHo(ala,s) = - (-1442.87 kJ/mol) = 1442.87 kJ/mol

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