PLEASE ANSWER ALL 21 QUESTIONS FOR MAX POINTS......... Concept Explorations 7.23
ID: 779958 • Letter: P
Question
PLEASE ANSWER ALL 21 QUESTIONS FOR MAX POINTS......... Concept Explorations 7.23. Light, Energy, and the Hydrogen Atom a. Which has the greater wavelength, blue light or red light? b. How do the frequencies of blue light and red light compare? c. How does the energy of blue light compare with that of red light? d. Does blue light have a greater speed than red light? e. How does the energy of three photons from a blue light source compare with the energy of one photon of blue light from the same source? How does the energy of two photons corresponding to a wavelength of 451 nm (blue light) compare with the energy of three photons corresponding to a wavelength of 704 nm (red light)? f. A hydrogen atom with an electron in its ground state interacts with a photon of light with a wavelength of 1.22Explanation / Answer
Ans 7.23
a). Red light has greater wavelength than blue light
b). Frequency of blue light is greater than red light
c). Energy of blue light is more than red light as energy is inversely proportional to wavelength
d). Blue and red light travel with same speed in VACCUM but in any other medium blue light travel with less speed than red light.
e). Energy of three photons of same source of blue light will be 3 times the energy of one photon.
Therefore, energy of 704 nm (red light) will be less than energy of 451 nm (blue light).
f). No, it can make transition to higher level as we can calculate it by formula
E = -2.178 x 10-18 J (Z^2/n^2)
E = energy, Z = nuclear charge and n = energy level.
This equation can be used to calculate the change in energy of an electron when the electron changes orbits.
Because energy of this photon does not match with energy difference between any 2 level of H2 .
g). 1 mole of H2 contains NA (6.022 x 10^23) electrons ,Therefore they will need NA number of photons to excite them.
Difference between energy in 1 and 3 level can be calculated using above formula
Energy required in photon = 1.936 x 10^-19
Therefore wavelength of photon = hc/E
= (6.626 x 10^-34 J*s)(3.0 x 108 m/s) / 1.936 x 10^-18 J = 1.027 x 10^-7 m = 1027 angstroms.
7.24
a). Ground state energy level are same for both X and H
b). H has lower energy in n=2 because magnitude is inversely proportional to n^2 in H but it is to n^ in X. Therefore magnitude of energy of H will be more than X but it is negative energy therefore it will be less.
c). Spacing of levels in H is less than in X.
d). Energy of photon emitted from H is more therefore frequency photon emitted by H will be more.
e). H will require more energy to completely remove electron.
f). No this can not give same transition in X because energy difference between level 2 and 5 of X is not equal to that of H.
8.29
a). X wil belong to Alkaline Earth metals because of large difference in second and third ionisation energy values as they get stable form after emitting 2 electrons.
b). Element X will have charge +2 when it will form ion.
c). No Y can%u2019t be placed in same period as X rather it would be placed in same group as X.
d). Atom Y will be smaller than X because than only it will have higher first ionisation energy.
8.30
a). W can be non metal as they have higher electron affinity and Z can be metal. Therefore W ion will be negative and Z ion will be positive So, W ion will require higher energy to remove electron.
b). Z will have higher atomic radius than W because As you go across a period, electrons are added to the same energy level. At the same time, protons are being added to the nucleus. The concentration of more protons in the nucleus creates a "higher effective nuclear charge." In other words, there is a stronger force of attraction pulling the electrons closer to the nucleus resulting in a smaller atomic radius.
c). Z will have smaller first ionisation energy because it increase as we go towards non metals in periodic table it increases.
d). NO, valence electrons of W feels greater nuclear charge because as we move towards non metals nuclear charge increases while electons are uniformly distributed in outer shell.
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