1.A beam of protons is moving in the + x direction with a speed of 29.3 km/s thr

Question

1.A beam of protons is moving in the +x direction with a speed of 29.3 km/s through a region in which the electric field is perpendicular to the magnetic field. The beam is not deflected in this region. If the magnetic field has a magnitude of 0.372 T and points in the +z direction, what is the magnitude of the electric field?

2. What is the direction of the electric field?
-y
+y
-x
+z
-z
+x

3. Would electrons that have the same velocity as the protons be deflected by these fields? If so, in what direction would they be deflected?
Yes, +y
Yes, +z
Yes, -z
Yes, +x
Yes, -y
Yes, -x
No

Explanation / Answer

1. Magnetic force = electric field (For undeflected path)

qvB = qE

E = vB = 29.3 x 103 x 0.372 = 10899.6 V/m

Hence electric field = 10899.6 V/m

2. As per right hand rule the magnetic force acts in -y direction so the electric field should act in +y direction

hence direction of electric field = +y direction

3. No, they will not be deflected

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